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Question
What is the oxidation number of gold in the complex [AuCl4]1−?
Options
+4
+3
+2
+1
MCQ
Solution
+3
Explanation:
In [AuCl4]1− let the oxidation number of Au = x
x + 4(−1) = −1
x − 4 = −1
x = −1 + 4
x = +3
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Chemical Properties of Elements of Groups 16, 17 and 18
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