Question

What is the product of the following reaction?

\[\ce{H3C - C ≡ CH + H - OH ->[{40%}H2SO4][{1%}HgSO4] ?}\]

Options

• Acetone

• propan-2-ol

• ethanal

• Propanal

Answer 1

Acetone

Explanation:

Propanone is the main result when propyne is treated with aqueous H₂SO₄ in the presence of HgSO₄.

\[\begin{array}{cc}
\ce{\underset{\underset{(Propyne)}{Methyl acetylene}}{H3C - C ≡ CH} + H - OH ->[{40%}H2SO4][{1%}HgSO4] H3C - C = CH2 ⇌[Tautomerism] H3C - C - CH3}\\
\phantom{....................................}|\phantom{...........................}||\phantom{}\\
\phantom{...................................}\ce{\underset{Prop-1-en-2-ol}{OH}}\phantom{..................}\ce{\underset{\underset{(Propanone)}{Acetone}}{O}}\phantom{}
\end{array}\]