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Question
What is the relation between `("d"["H"_2])/"dt" and ("d"["NH"_3])/"dt"`?
Options
`1/2 ("d"["NH"_3])/"dt" = ("d"["H"_2])/"dt"`
`("d"["NH"_3])/"dt" = 2/3 ("d"["H"_2])/"dt"`
`2/3 ("d"["NH"_3])/"dt" = ("d"["H"_2])/"dt"`
`("d"["NH"_3])/"dt" = ("d"["H"_2])/"dt"`
MCQ
Solution
`("d"["NH"_3])/"dt" = 2/3 ("d"["H"_2])/"dt"`
Explanation:
\[\ce{N2(g) + 3H2(g) <=> 2NH3(g)}\]
Rate expression can be written as,
`(- "d"["N"_2])/"dt" = (- 1)/3 ("d" ["H"_2])/"dt" = 1/2 ("d"["NH"_3])/"dt"`
`- 1/3 ("d"["H"_2])/"dt" = 1/2 ("d"["NH"_3])/"dt"`
`therefore ("d"["NH"_3])/"dt" = - 2/3 ("d"["H"_2])/"dt"`
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