Question

What is the resolving power of telescope if the diameter of the objective of the telescope is 1.22 m and the wavelength of light is sooo A?

Answer 1

Given : D = 1.22 m, λ = 5000 Å = 5 × 10^-7 m

To find: Resolving power of the telescope = ? 

`R. P.  D/(1.22lambda)`

= `1.22/(1.22xx5 xx 10^-7)`

= `(10 xx 10^6)/5` 

= 2 × 10⁶