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Question
What is the values of `cos^-1 (cos (7pi)/6)`
Options
`(7pi)/6`
`(5pi)/6`
`pi/3`
`pi/6`
MCQ
Solution
`(5pi)/6`
Explanation:
`cos^-1 (cos (7pi)/6) = cos^-1 (cos - (7pi)/6)`
= `cos^-1 [cos(2pi - (7pi)/6)]`
= `cos^-1 [cos (5pi)/6]`
= `(5pi)/6`
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