Question

What mass of an oxygen gas will occupy 8.21 L of volume at 1 atm pressure and 400 K temperature?

Options

• 8 g

• 4 g

• 2 g

• 12 g

Answer 1

8 g

Explanation:

PV = nRT

∴ PV = `"m"/"M" "RT"`

∴ m = `"PVM"/"RT"`

= `(1  "atm" xx 8.21  "L" xx 32  "g mol"^-1)/(0.0821  "L atm mol"^-1  "K"^-1 xx 400  "K")`

= 8 g