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Question
What p.d. is needed to send a current of 6 A through an electrical appliance having a resistance of 40 Ω?
Solution
We know that V = IR
Here, I = 6 A
R = 40 Ω
So, V = 6 x 40
V = 240 V
So 240 V is the potential difference needed to send a current of 6 A through an electrical appliance that has a resistance of 40 Ω.
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