Advertisements
Advertisements
Question
What should be the ratio of area of cross section of the master cylinder and wheel cylinder of a hydraulic brake so that a force of 15 N can be obtained at each of its brake shoe by exerting a force of 0.5 N on the pedal ?
Solution
Let the ratio of area of cross - section of the master cylinder and wheel cylinder be A1 : A2
Force on pedal , F1 = 0.5 N
Force on break shoe , F2 = 15 N
By the principle of hydraulic machine,
Pressure on narrow piston = pressure on wider piston
or , `F_1/A_1 = F_2/A_2`
or , `F_1/F_2 = A_1/A_2`
or , `A_1/A_2 = 0.5/15`
or , `A_1/A_2 = 1/30`
Thus , the required ratio is 1:30
APPEARS IN
RELATED QUESTIONS
Name and state the principle on which a hydraulic press works. Write one use of hydraulic press.
A force of 50 kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the diameters of the pistons are 5 cm and 25 cm respectively.
Select the correct option.
One Pascal is equal to
Select the correct option.
Pressure at a point inside a liquid does not depend on
The pressure in the water pipe on the ground floor of a building is 40000 pascals, whereas on the first floor it’s 10000 pascals. Find the height of the first floor. (Acceleration due to gravity g = 10 ms−2)
State two applications of Pascal's law.
Analogy
Pascal’s law: ______:: Surface tensin: ______.
A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ______ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
