Question

What will be the current flowing through the 6 kΩ resistor in the circuit shown, where the breakdown voltage of the Zener is 6V?

Options

• `2/3`mA

• 1 mA

• 10 mA

• `3/2`mA

Answer 1

`2/3`mA

Explanation:

Zener breakdown voltage = 6 V

`therefore "Potential across 6" kOmega` = (10 - 6) = 4 V

`"Current through the 6" kOmega`

`= 4/6000`

` = 2/3000 "A"`

` = 2/3"mA"`