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Question
What will be the formula of an oxide of iodine (atomic mass = 127) which contains 25.4 g of iodine and 8g of oxygen?
Options
\[\ce{I2O}\]
\[\ce{I2O3}\]
\[\ce{I2O5}\]
\[\ce{I2O7}\]
MCQ
Solution
\[\ce{I2O5}\]
Explanation:
∵ 25.4 g of I2 combines with 8g of oxygen.
∴ 254 g of I2 will combines with 80 g of oxygen.
| Element | Mass % | Atomic mass | Moles of element | Molar ratio | Simplest whole number ratio |
| I | 25.4 | 127 | `25.4/127` = 0.2 | `0.2/0.2 = 1` | 2 |
| O | 8 | 16 | `8/16 = 0.5` | `0.5/0.2 = 2.5` | 5 |
∴ Formula of oxide of iodine will be I2O5.
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Oxygen and Compounds of Oxygen
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