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Question
What will be the value of pH of 0.01 mol dm–3 \[\ce{CH3COOH}\] (Ka = 1.74 × 10–5)?
Options
3.4
3.6
3.9
3.0
Solution
3.4
Explanation:
pH for weak acid is given by the following equation:
pH = `1/2[pK_a - log C]`
= `21 [ - log(1.74 xx 10^(-5} - log 0.01]`
= 3.4
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