Question

What would be the main product when propene reacts with HBr?

Options

• \[\begin{array}{cc}
  \phantom{....}\ce{H}\phantom{..}\ce{H}\phantom{.}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \ce{CH3-C-C-H}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \phantom{...}\ce{Br}\phantom{.}\ce{H}\phantom{}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{....}\ce{H}\phantom{..}\ce{H}\phantom{.}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \ce{CH3-C-C-H}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \phantom{....}\ce{H}\phantom{..}\ce{Br}\phantom{}
  \end{array}\]

• Both \[\begin{array}{cc}
  \phantom{....}\ce{H}\phantom{..}\ce{H}\phantom{.}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \ce{CH3-C-C-H}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \phantom{...}\ce{Br}\phantom{.}\ce{H}\phantom{}
  \end{array}\] and \[\begin{array}{cc}
  \phantom{....}\ce{H}\phantom{..}\ce{H}\phantom{.}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \ce{CH3-C-C-H}\\
  \phantom{...}|\phantom{...}|\phantom{}\\
  \phantom{....}\ce{H}\phantom{..}\ce{Br}\phantom{}
  \end{array}\]

• Br–CH₂–CH=CH₂

Answer 1

\[\begin{array}{cc}
\phantom{....}\ce{H}\phantom{..}\ce{H}\phantom{.}\\
\phantom{...}|\phantom{...}|\phantom{}\\
\ce{CH3-C-C-H}\\
\phantom{...}|\phantom{...}|\phantom{}\\
\phantom{...}\ce{Br}\phantom{.}\ce{H}\phantom{}
\end{array}\]

Explanation:

\[\begin{array}{cc}
\ce{CH3-CH=CH2 ->[HBr] CH3-CH-CH3}\\
\phantom{...................}|\\
\phantom{....................}\ce{Br}
\end{array}\]