Question

When a current is passed through a tangent galvanometer, it gives a deflection of 30° for 60° correction, the current must be

Options

• 1 amp

• `2sqrt(3)` amp

• 4 amp

• 6 amp

Answer 1

6 amp

Explanation:

As, `i_2/i_1 = tan theta_2/tan theta_1`

∴ `i_2/2 = (tan 60^circ)/(tan 30^circ) = sqrt(3)/(1sqrt(3))` = 3

i₂ = 6 amp