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Question
When a light of wavelength 4000 Å falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 6000 Å is sufficient for photo emission. The work functions of the two emitters are in the ratio of ____________.
Options
3 : 2
3 : 5
5 : 3
2 : 3
Solution
When a light of wavelength 4000 Å falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 6000 Å is sufficient for photo emission. The work functions of the two emitters are in the ratio of 3 : 2.
Explanation:
`phi = ("hc")/lambda_0`
`"Case (i)" lambda_1 = ("hc")/phi_1`
`"Case (ii)" lambda_2 = ("hc")/phi_2`
Dividing equation (i) by (ii),
`therefore lambda_1/lambda _2 = (phi_0)_2/(phi_0)_1 = (6000 xx10^-10)/(4000 xx 10^-10) = 3/2`