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Question
When a string is stretched by 0.5 cm, its potential energy is U. If the string is stretched by 2 cm, then its potential energy will be:
Options
4U
8U
16U
32U
MCQ
Solution
16U
Explanation:
U α l2
∴ `"U"_2/"U"_1 = (2/0.5)^2`
= 16
∴ U2 = 16U
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