Question

When CH₃CH₂CHCl₂ is treated NaNH₂ product formed is:-

Options

• CH₃ – CH = CH₂

• CH₃ – C ≅ CH

• \[\begin{array}{cc}
  \phantom{.........}\ce{NH2}\\
  \phantom{....}/\\
  \ce{CH3CH2CH}\phantom{..........}\\
  \phantom{....}\backslash\\
  \phantom{.........}\ce{NH2}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{......}\ce{Cl}\\
  \phantom{..}/\\
  \ce{CH3CH2C}\phantom{..........}\\
  \phantom{..}\backslash\\
  \phantom{.......}\ce{NH2}
  \end{array}\]

Answer 1

CH₃ – C ≅ CH

Explanation:

\[\ce{CH3 - CH2CH2Cl ->[NaH2][Δ] CH3 - CH = CHCl -> CH3 - C ≅ CH}\]