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Question
When ethyl methyl ether is treated with cold concentrated HI, it gives two products. Products formed are ____________.
Options
CH3l + C2H5OH
CH3CH2OH + CH3OH + CH3l
CH3OH + C2H5l
CH3CH2I + CH3l + H2O
MCQ
Fill in the Blanks
Solution
When ethyl methyl ether is treated with cold concentrated HI, it gives two products. Products formed are CH3l + C2H5OH.
Explanation:
\[\ce{\underset{Ethyl methyl ether}{CH3OC2H5} + HI ->[Cold] \underset{Methyl iodide}{CH3I} + \underset{Ethyl alcohol}{C2H5OH}}\]
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