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When an Object is Placed at a Distance of 50 Cm from a Concave Spherical Mirror, the Magnification Produced Is, `-1/2`. Where Should the Object Be Placed to Get a Magnification Of, `-1/5`? - Science

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Question

When an object is placed at a distance of 50 cm from a concave spherical mirror, the magnification produced is, `-1/2`. Where should the object be placed to get a magnification of, `-1/5`? 

Solution

Given,
Magnification `(m)=-1/2`

Distance of the object (u) = −50 cm
We have to find the distance of the object when the magnification is `=-1/5`
Therefore, using the magnification formula, we get  
`m=-v/u` 
v=-mu 
`v=-(-1/2xx-50) ` 
`v=-25` cm 
Now, using the mirror formula, we get 
`1/f=1/u+1/v` 
`1/f=1/-"mu"+1/u` 
`1/f=1/-25+1/-50` 
or` 1/f=-2/50-1/50=3/-50` 
or `f=-50/3` cm 

Now,
Magnification = `m=-1/5`

Therefore, using the mirror formula, we get 

`1/f=1/-"mu"+1/u` 

`or -3/50=(-5)/-5+1/u` 

`or (-3)/50=5/u+1/u` 

`or (-3)/50 =6/4` 

`u=-50xx6/3=-100` cm  

The object should be placed in front of the mirror at a distance of 100 cm to get the magnefiction of `-1/5` 

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Chapter 4: Reflection of Light - Exercise 5 [Page 199]

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Lakhmir Singh Physics (Science) [English] Class 10
Chapter 4 Reflection of Light
Exercise 5 | Q 27 | Page 199

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