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Question
When propionamide reacts with Br2 in the presence of alkali the product is ______.
Options
CH3CH2CH2NH2
CH3CH2NH2
C3H7CN
C2H5CN
MCQ
Fill in the Blanks
Solution
When propionamide reacts with Br2 in the presence of alkali the product is CH3CH2NH2.
Explanation:
\[\begin{array}{cc}
\ce{CH3-CH2-C-NH2 ->[KOH][Br2] CH3CH2-NH2 + KBr + KHCO3}\\
||\phantom{.................................}\\
\ce{O}\phantom{.................................}
\end{array}\]
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