Question

When the displacement of a particle executing simple harmonic motion is half of its amplitude, the ratio of its kinetic energy to potential energy is:

Options

• 1 : 3

• 2 : 1

• 3 : 1

• 1 : 2

Answer 1

3 : 1

Explanation:

Given, x = `"A"/2`

∴ from x = A sin ωt

⇒ ωt = 30°

And, `"KE"/"PE" = cot^2 ω"t" = (sqrt3)^2` = 3