Question

When the pressure on the gas is increased to 4 times that of initial value, volume becomes `1/3`rd that of initial. Percentage difference in temperature will be ______.

Options

• 76%

• 67%

• 16%

• 33%

Answer 1

When the pressure on the gas is increased to 4 times that of initial value, volume becomes `1/3`rd that of initial. Percentage difference in temperature will be 33%.

Explanation:

Being the same gas, n =constant From equation of states,

`("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`

`therefore ("P"_1"V"_1)/"T"_1 = (4"P"_1"V"_1)/(3"T"_2`

`therefore "T"_2 = (4"T"_1)/3`

`therefore Delta "T"= "T"_2 - "T"_1 = 0.33 ≈ 33 %`