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Question
When the value of acceleration due to gravity 'g' becomes `(g/3)` above the earth's surface at height 'h' then relation between 'h' and 'R' is ______.
R =radius of the earth
Options
`h=R(sqrt3-1)`
`h=R(sqrt2-1)`
h = 2R
h = R
MCQ
Fill in the Blanks
Solution
When the value of acceleration due to gravity 'g' becomes `(g/3)` above the earth's surface at height 'h' then relation between 'h' and 'R' is `underline(h=R(sqrt3-1))`.
Explanation:
`g/3=(GM)/(R+h)^2` `g=(GM)/R^2`
`therefore g/3(R+h)^2=gR^2`
(R + h)2 = 3R2
`R +h=sqrt3R`
`therefore h=sqrt3R-R=(sqrt3-1)R`
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