Advertisements
Advertisements
Question
When the value of R in the balanced Wheatstone bridge, shown in the figure, is increased from 5 `Omega` to 7 `Omega`, the value of s has to be increased by 3 `Omega` in order to maintain the balance. What is the initial value of S?
Options
2.5 `Omega`
3 `Omega`
5 `Omega`
7.5 `Omega`
MCQ
Solution
7.5 `Omega`
Explanation:
`"P"/"Q" ="R"/"S"`
Since P and Q is constant `"P"/"Q"` will be constant
`therefore "R"/"S"` = constant
`"R"/"S" = 5/"S" = 7/("S"+3`
`=> 5("S"+3)` = 7S
`therefore` 15 = 2S
`therefore "S" = 7.5 Omega `
shaalaa.com
Is there an error in this question or solution?