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Question
When wavelength of incident radiation on the metal surface is reduced from 'λ1' to 'λ2', the kinetic energy of emitted photoelectrons is tripled. The work function of the metal is ______.
(h = Planck's constant, c =velocity of light)
Options
`"hc"/2 [(2lambda_2 - lambda_1)/(lambda_1lambda_2)]`
`"hc"[(3lambda_2 - lambda_1)/(lambda_1lambda_2)]`
`"hc"[(2lambda_2 - lambda_1)/(lambda_1lambda_2)]`
`"hc"/2[(3lambda_2 - lambda_1)/(lambda_1lambda_2)]`
Solution
When wavelength of incident radiation on the metal surface is reduced from 'λ1' to 'λ2', the kinetic energy of emitted photoelectrons is tripled. The work function of the metal is `underline("hc"/2[(3lambda_2 - lambda_1)/(lambda_1lambda_2)])`.
Explanation:
E = `"hc"/lambda_1 - phi_0`
3E = `"hc"/lambda_2 - phi_0`
3E = `"3hc"/lambda_1 - 3phi_0`
- - +
`0 = "hc"/lambda_2 - (3lambda"c")/lambda_1 + 3phi_0 - phi_0`
`(3lambda"c")/lambda_1 - "hc"/lambda_2 = 2phi_0`
`therefore phi_0 = "hc"/2[3/lambda_1 - 1/lambda_2]`
`= "hc"/2[(3lambda_2 - lambda_1)/(lambda_1lambda_2)]`