Question

Which compound would exhibit optical isomers?

Options

• 

• \[\begin{array}{cc}\ce{CH3}\phantom{....}\\
  |\phantom{......}\\\ce{C - OH}\\
  /\backslash\phantom{.......}\\
  \ce{H3C}\phantom{.}\ce{COOH}\phantom{....}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{.}\ce{HOOC}\phantom{....}\ce{H}\\
  \phantom{......}\backslash\phantom{...}/\\
  \phantom{......}\ce{C}\\
  \phantom{......}||\\
  \phantom{......}\ce{C}\\
  \phantom{......}/\phantom{.}\backslash\\
  \phantom{...........}\ce{H}\phantom{...}\ce{COOH}
  \end{array}\]

• 

Answer 1

Explanation:

Ortho-substituted biphenyl exhibit optical isomerism, both group are in a different plane.