Question

Which of the following alkyl halide is treated with sodium metal to obtain 2, 2, 3, 3 tetramethyl butane?

Options

• sec-butyl bromide

• n-propyl bromide

• n-butyl bromide

• tert butyl bromide

Answer 1

tert butyl bromide

Explanation:

Alkyl halides react with sodium in dry ether to produce hydrocarbons that have twice the amount of carbon atoms as the halide.

\[\ce{\underset{ter-butyl bromide}{2(CH3)3 CBr} ->[Na/Dry ether] \underset{2, 2, 3, 3 - tetramethyl butane}{H3C - C(CH3)2 - C(CH3)2} - CH3 \underset{bromide}{\underset{Sodium}{+ 2 NaBr}}}\]