Advertisements
Advertisements
Question
Which of the following are quadratic equation:
`(x -(1)/x)^2` = 0.
Solution
Given equation is
`(x -(1)/x)^2` = 0
⇒ `x^2 + (1)/(x^2) - 2x (1)/x` = 0
⇒ x4 + 1 - 2x2 = 0
⇒ x4 - 2x2 + 1 = 0
It is not a quadratic equation.
APPEARS IN
RELATED QUESTIONS
Which of the following are quadratic equation in x?
(2x+3)(3x+2)=6(x-1)(x-2)
`sqrt3x^2+11x+6sqrt3=0`
`3/x+1-1/2=2/(3x-1),x≠-1,1/3`
Find the value of 'p', if the following quadratic equations have equal roots:
x2 + (p − 3)x + p = 0
If x = −3 and x = `2/3` are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n.
If -1 and 3 are the roots of x2+px+q=0
then find the values of p and q
Solve :
`2x - 3 = sqrt(2x^2 - 2x + 21)`
If m and n are roots of the equation `1/x - 1/(x - 2) = 3`; where x ≠ 0 and x ≠ 2; find m × n.
Write the following quadratic equation in standard form ax2 + bx + c = 0 : x (x + 3) = 7
Write the quadratic equation 3y2 = 10y +7 in the standard form ax2 + bx + c = 0 .
