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Question
Which of the following conversion explains the acidic nature of alcohols?
Options
\[\ce{C2H5OH ->[PCl5][\Delta] C2H5Cl + HCl + POCl3}\]
\[\ce{C2H5 - OH ->[HBr][\Delta] C2H5 - Br + H2O}\]
\[\ce{C2H5OH ->[95% H2SO4][443 K] C2H4 + H2O}\]
\[\ce{2C2H5 - OH ->[Na] 2 C2H5 - ONa + H2}\]
MCQ
Solution
\[\ce{2C2H5 - OH ->[Na] 2 C2H5 - ONa + H2}\]
Explanation:
Since 'H' atom of C2H2OH is replaced by 'Na' atom, it means 'H' is acidic.
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