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Question
Which of the following is not equal to 1?
Options
`(2^3 xx 3^2)/(4 xx 18)`
`[(-2)^3 xx (-2)^4] ÷ (-2)^7`
`(3^0 xx 5^3)/(5 xx 25)`
`2^4/(7^0 + 3^0)^3`
Solution
`bb(underline(2^4/(7^0 + 3^0)^3)`
Explanation:
Let us solve the expressions
a. `(2^3 xx 3^2)/(4 xx 18) = (2 xx 2 xx 2 xx 3 xx 3)/(4 xx 18)`
= `(4 xx 18)/(4 xx 18)`
= 1
b. `[(-2)^3 xx (-2)^4] ÷ (-2)^7 = ((-2)^3 xx (-2)^4)/(-2)^7`
= `(-2)^(3+4)/(-2)^7` ......[∵ am × an = am+n]
= `(-2)^7/(-2)^7` ......`[∵ a^m/a^n = a^(m-n)]`
= 1
c. `(3^0 xx 5^3)/(5 xx 25) = (1 xx 5 xx 5 xx 5)/(5 xx 25)`
= `(5 xx 25)/(5 xx 25)` ......[∵ a0 = 1]
= 1
d. `2^4/(7^0 + 3^0)^3 = 2^4/(1 + 1)^3` ......[∵ a0 = 1]
= `2^4/2^3` = 24–3 ......`[∵ a^m/a^n = a^(m-n), m > n]`
= –21 = 2
Hence, `2^4/(7^0 + 3^0)^3` is not equal to 1.
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