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Question
Which of the following transition will have highest emission wavelength?
Options
n = 2 to n = 1
n = 1 to n = 2
n = 2 to n = 5
n = 5 to n = 2
MCQ
Solution
n = 5 to n = 2
Explanation:
To obtain an emission wavelength electron must transit from higher energy state to lower.
∴ For transition from n = 2 ton= 1,
`1/lambda_21 = "R" [1/1^2 - 1/2^2] = (3"R")/4`
For transition from n = 5 to n = 2,
`1/lambda_52 = "R" [1/2^2 - 1/5^2] = (21"R")/100`
`therefore 1/lambda_52 < 1/lambda_21`
`therefore lambda_52 > lambda_21`
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