Question

Which of the following would not give 2-phenylbutane as the major product in a Friedel-Crafts alkylation reaction?

Options

• 1-butene + HF

• 2-butanol + H₂SO₄

• Butanoyl chloride + AlCl₃ then Zn, HCl

• Butyl chloride + AlCl₃

Answer 1

Butanoyl chloride + AlCl₃ then Zn, HCl

Explanation:

The Friedal-Crafts alkylation reaction produces propyl phenyl ketone, further reduced by Clemmensen’s to produce butyl benzene.

\[\ce{C6H6 + CH3CH2CH2COCl ->[AlCl3] C6H5COCH2CH2CH3 ->[Zn-Hg/HCl] \underset{Butyl benzene}{C6H5CH2CH2CH2CH3}}\]