Question

Which one of the following has sp³, sp², or sp hybrid orbitals in the ratio 6 : 3 : 2?

Options

• \[\ce{H3C - CH = CH - CH2 - C ≡ C - CH3}\]

• \[\ce{H3C - CH = CH - CH2 - C ≡ CH}\]

• \[\ce{H3C - CH2 - C ≡ C - CH = CH2}\]

• \[\ce{H3C - CH = CH - C ≡ CH}\]

Answer 1

\[\ce{H3C - CH = CH - CH2 - C ≡ C - CH3}\]

Explanation:

sp³        sp²     sp²      sp²      sp    sp     sp³

\[\ce{H3C - CH = CH - CH2 - C ≡ C - CH3}\]

Number of sp³ hybridised carbon atoms = 3

∴ Number of sp³ hybrid orbitals =  3 × 4 = 12

Number of sp² hybridised carbon atoms = 2

∴ Number of sp² hybrid orbitals = 2 × 3 = 6

Number of sp hybridised carbon atoms = 2

∴ Number of sp hybrid orbitals = 2 × 2 = 4

Thus, the ratio is 6 : 3 : 2.