Advertisements
Advertisements
Question
Which polynomial is to be added to 4m + 2n + 3 to get the polynomial 6m + 3n + 10?
Solution
The required polynomial can be obtained by subtracting the polynomial 4m + 2n + 3 from 6m + 3n + 10.
∴ Required polynomial
∴ (4m + 2n + 3) + p(a) = (6m + 3n + 10)
∴ p(a) = (6m + 3n + 10) − (4m + 2n + 3)
= 6m + 3n + 10 − 4m − 2n − 3
= 6m − 4m + 3n − 2n + 10 − 3
= 2m + n + 7
Thus, the polynomial 2m + n + 7 is to be added to 4m + 2n + 3 to get the polynomial 6m + 3n + 10.
APPEARS IN
RELATED QUESTIONS
The tens and units place of a two digit number is m and n respectively. Write the polynomial which represents the two digit number.
Add the given polynomials.
`x^3 - 2x^2 - 9 ; 5x^3 + 2x + 9`
Subtract the second polynomial from the first.
`2ab^2 + 3a^2b - 4ab ; 3ab - 8ab^2 + 2a^2b`
Multiply the given polynomial.
`2x ; x^2 - 2x - 1`
Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor × Quotient + Remainder’.
`x^3 - 64 ; x - 4`
Add the following polynomial.
`7x^4 - 2x^3 + x + 10 ; 3x^4 + 15x^3 + 9x^2 - 8x + 2`
Subtract the second polynomial from the first.
`5x^2 - 2y + 9 ; 3x^2 + 5y - 7`
Multiply the following polynomial.
`(m^3 - 2m + 3)(m^4 - 2m^2 + 3m + 2)`
Multiply the following polynomial.
`(5m^3 - 2) (m^2 - m + 3)`
