Question

Which sodium salt will be heated with soda lime to obtain propane?

Options

• \[\begin{array}{cc}
  \ce{CH3 - CH2 - C - O^-Na^+}\\
  \phantom{....}||\\
  \phantom{....}\ce{O}
  \end{array}\]

• \[\begin{array}{cc}
  \ce{CH3 - CH2 - CH2 - C - O^-Na^+}\\
  \phantom{...........}||\\
  \phantom{...........}\ce{O}
  \end{array}\]

• \[\begin{array}{cc}
  \ce{(CH3)2 - CH - C - O^-Na^+}\\
  \phantom{......}||\\
  \phantom{......}\ce{O}
  \end{array}\]

• both \[\begin{array}{cc}
  \ce{ CH3 - CH2 - CH2 - C - O^-Na^+}\\
  \phantom{...........}||\\
  \phantom{...........}\ce{O}
  \end{array}\] and \[\begin{array}{cc}
  \ce{(CH3)2 - CH - C - O^-Na^+}\\
  \phantom{......}||\\
  \phantom{......}\ce{O}
  \end{array}\]

Answer 1

both \[\begin{array}{cc}
\ce{ CH3 - CH2 - CH2 - C - O^-Na^+}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\] and \[\begin{array}{cc}
\ce{(CH3)2 - CH - C - O^-Na^+}\\
\phantom{......}||\\
\phantom{......}\ce{O}
\end{array}\]

Explanation:

\[\ce{(CH3)2-CH-CO\overset{-}{O}Na^+ ->[CaO][NaOH] CH3-CH2-CH3}\]