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Question
Why is bond order of Be2 molecule zero?
(Nb = bonding electrons, Na = antibonding electrons)
Options
Nb > Na
Nb = Na
`"N"_"b"/"N"_"a"` = Zero
Nb < Na
MCQ
Solution
Nb = Na
Explanation:
In Be2 molecule,
`sigma_(1"s"^2) sigma_(1"s"^2)^* sigma_(2"s"^2) sigma_(2"s"^2)^*`
Nb = 4, Na = 4
Bond order = `("N"_"b" - "N"_"a")/2` = 0
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Parameters of Covalent Bond
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