Question

Without solving, comment upon the nature of roots of the following equations

6x² – 13x +4 =0

Answer 1

6x^2 - 13x + 4 =0

a = 6, b = -13 and c = 4

∴ Discriminant = `b^2 - 4ac`

`= (-13)^2 - 4(6)(4)`

= 169 - 96 = 73

Since 73 is not a perfect square, roots are irrational

Since   D > 0, then equation has two irrational and unequal roots.