Question

Without solving, examine the nature of roots of the equation 4x² – 4x + 1 = 0

Answer 1

Comparing 4x² – 4x + 1 = 0 with ax² + bx + c = 0;

we get: a = 4, b = – 4, and c = 1

D = b² – 4ac = (–4)² – 4 × 4 × 1

= 16 – 16 = 0

∴ Roots are real and equal.