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Question
Work done to blow a bubble of volume V is W. The work done in blowing a bubble of volume 2V will be ______.
Options
(2)1/3 W
2 W
(4)1/3 W
4 W
Solution
Work done to blow a bubble of volume V is W. The work done in blowing a bubble of volume 2V will be (4)1/3 W.
Explanation:
From the definition of surface tension (T), the surface tension of a liquid is equal to the work (W) required to increase the surface area (A) of the liquid film by unity at constant temperature.
∴ W = T × ΔA
Since, surface area of a sphere is 4πR2 and there are two free surfaces, we have
W = T × 8πR2 ...(i)
and volume of sphere = `4/3pi"R"^3`
i.e, V = `4/3pi"R"^3`
⇒ R = `((3"V")/(4pi))^(1//3)` ...(ii)
From eqs. (i) and (ii) we get,
⇒ W ∝ V2/3
W = T × 8π × `((3"V")/(4pi))^(2//3)`
∴ W1 ∝ `"V"_1^(2//3)` and W2 ∝ `"V"_2^(2//3)`
∴ `"W"_2/"W"_1=((2"V"_1)/"V"_1)^(2//3)`
⇒ W2 = 22/3 W1 = 41/3W