Question

Write a menu-driven program to display the pattern as per the user’s choice. 

For an incorrect option, an appropriate error message should be displayed.

Answer 1

import java.io.*;
import java.util.Scanner;
class Pattern {
public static void main(String args[]) throws IOException {
Scanner sc = new Scanner(System.in);
System.out.println(“::::MENU::::”)
System.out.println(” 1. To display ABCD Pattern”);
System.out.print(” 2. To display Word Pattern”);
System.out.print(“Enter your choice:”);
int ch= sc.nextlnt();
switch(ch) {
case 1:
for (char i = ‘E’; i > = ‘A’; i- -){
for(char j = ‘A’;j <=i;j + +){
System.out.print(j);
}
System.out.prindn( );
}
break;
case 2:
String S = “BLUE”;
for (int i = 0; i < S.length(); i+ +) {
for(int j = 0; j < =i; j + +) {
System.out.print(S.charAt(i));
}
System.out.println();
}
break;
default:
System.out.println(“Invalid Input”);
break;
}
}
}