Question

Write a program to input a number and check whether it is a perfect square or not. If the number is not a perfect square then find the least number to be added to input number, so that the resulting number is a perfect square. 

Example 1:
Sample Input: 2025
`sqrt(2025)` = 45
Sample Output: It is a perfect square.

Example 2:
Sample Input: 1950
`sqrt(1950)` = 44.1588.........
Least number to be added = 452 − 1950 = 2025 − 1950 = 75

Answer 1

import java.util.*; 

public class Q9 
{
   public static void main(String args[])
   {
       Scanner in = new Scanner(System.in);
       System.out.print("Enter a number: ");
       int num = in.nextlnt(); 

       if (num < O) {
         System.out. println("Cannot calculate square root of negative number.");
         System.exit(O); 
       }
       else
       {
         double sqRoot = Math.sqrt(num); 
         double sqRoot1 = Math.floor(sqRoot);
         double diff = sq Root − sqRoot1; 
         if (diff == 0) {
            System.out.println(num + " is a perfect square.");
         }
         else {
            sqRoot 1 += 1;
            double temp = Math.pow(sqRoot1, 2);
            diff = temp − num; 
            System.out.println(num + " is not a perfect square.");
            System.out.println("Least number to be added = " + diff);
         }   
      }
   }
}