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Question
Write the expression for the de Broglie wavelength associated with a charged particle having charge ‘q’ and mass ‘m’, when it is accelerated by a potential V.
Solution
The charged particle has a mass m and charge q.
The kinetic energy of the particle is equal to the work done on it by the electric field.
`k=qV => 1/2mv^2=qV => p =sqrt(2mqV)`
`therefore \text { de Broglie wavelengh associated with the particle}, lambda = h/p = h/sqrt(2mqV)`
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