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Question
Write the following numbers using positive indices.
`(1/6)^-3`
Sum
Solution
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(1/6)^-3`
`= 1/(1/6)^3`
`= (6/1)^3`
`= 6^3`
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Say true or false and justify your answer:
23 > 52
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`((1/7)^-3)^4`
Write the following number using positive indices.
`(2/7)^-2`
Solve: `((2/5)^(-2))^3`.
If 2m – 1 + 2m + 1 = 640, then find m
Simplify and express the following in exponential form:
45 × 42 × 44
How many zeros are there in 10010?
`(6/13)^10 ÷ [(6/13)^5]^2 = (6/13)^-`
(–3)4 = –12
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
