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Maharashtra State BoardSSC (English Medium) 6th Standard

Write the Given Information as an Equation and Find Its Solution. Archana Bought Some Kilograms of Wheat. She Requires 12kg per Month and She Got Enough Wheat Milled for 3 Months. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Write the given information as an equation and find its solution.

Archana bought some kilograms of wheat. She requires 12 kg per month and she got enough wheat milled for 3 months. After that, she had 14 kg left. How much wheat had Archana bought altogether?

Sum

Solution 1

Let the weight of wheat bought by Archana altogether be x kg.

According to the given condition,

Weight of wheat bought by Archana altogether − Weight of the wheat used in 3 months = Amount of wheat left with Archana

∴ x kg − 12 kg/month × 3 months = 14 kg

⇒ x − 36 = 14

⇒ x − 36 + 36 = 14 + 36 (Add 36 to both sides)

⇒ x + 0 = 50

⇒ x = 50

Thus, the weight of wheat bought by Archana altogether is 50 kg. 

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Solution 2

Step 1: Calculate the total wheat required for 3 months

Archana uses 12 kg of wheat per month. For 3 months, the total wheat required is:

12 × 3 = 36 kg

Step 2: Add the remaining wheat

After using wheat for 3 months, Archana still had 14 kg left. Therefore, the total amount of wheat she originally bought is:

36 kg (used) + 14 kg (left) = 50 kg

Final Answer:

Archana bought 50 kg of wheat altogether.

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Chapter 10: Equations - Practice Set 27 [Page 55]

APPEARS IN

Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 10 Equations
Practice Set 27 | Q 5.3 | Page 55
Balbharati Integrated 6 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.1 Equations
Practice Set 27 | Q 5. (3) | Page 50
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