Question

Write the given rational numbers in ascending order:

${\displaystyle \frac{-1}{3},\frac{-2}{9},\frac{-4}{3}}$

Answer 1

${\displaystyle \frac{-1}{3},\frac{-2}{9},\frac{-4}{3}}$

By converting them to fractions

${\displaystyle \frac{-1}{3}=\frac{-1\times 3}{3\times 3}=\frac{-3}{9}}$;

${\displaystyle \frac{-2}{9}=\frac{-2}{9}}$;

${\displaystyle \frac{-4}{3}=\frac{-4\times 3}{3\times 3}=\frac{-12}{9}}$

As -12 < -3 < -2,

${\displaystyle \frac{-4}{3}<\frac{-1}{3}<\frac{-2}{9}}$