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Question
Write the logarithmic equation for:
E = `(1)/(2)"m v"^2`
Solution
E = `(1)/(2)"m v"^2`
Considering log on both the sides, we get
logE = `"log"(1/2 "m v"^2)`
= `"log"(1)/(2) + "log" "m" + "log" "v"^2`
= log1 - log2 + logm + 2logv
= logm + 2logv - log2.
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