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Question
Write the outputs of the SQL queries based on the relations Teacher and Placement given below:
Table: Teacher
| T_ID | Name | Age | Department | Date_of_join | Salary | Gender |
| 1 | Arunan | 34 | Computer Sc | 2019-01-10 | 12000 | M |
| 2 | Saman | 31 | History | 2017-03-24 | 20000 | F |
| 3 | Randeep | 32 | Mathematics | 2020-12-12 | 30000 | M |
| 4 | Samira | 35 | History | 2018-07-01 | 40000 | F |
| 5 | Raman | 42 | Mathematics | 2021-09-05 | 25000 | M |
| 6 | Shyam | 50 | History | 2019-06-27 | 30000 | M |
| 7 | Shiv | 44 | Computer Sc | 2019-02-25 | 21000 | M |
| 8 | Shalakha | 33 | Mathematics | 2018-07-31 | 20000 | F |
Table: Placement
| P_ID | Department | Place |
| 1 | History | Ahmedabad |
| 2 | Mathematics | Jaipur |
| 3 | Computer Sc | Nagpur |
- SELECT Department, avg(salary) FROM Teacher GROUP BY Department;
- SELECT MAX(Date_of_Join), MIN(Date_of_Join) FROM Teacher;
- SELECT Name, Salary, T.Department, Place FROM Teacher T, Placement P WHERE T.Department = P.Department AND Salary>20000;
- SELECT Name, Place FROM Teacher T, Placement P WHERE Gender = ’F’ AND T.Department = P.Department;
Solution
Department Avg(Salary) Computer Sc 16500.00 History 30000.00 Mathematics 25000.00
Max(Date_of_Join) Min(Date_of_Join) 2021-09-05 2017-03-04
Name Salary Department Place Randeep 30000 Mathematics Jaipur Samira 40000 History Ahmedabad Raman 25000 Mathematics Jaipur Shyam 30000 History Ahmedabad Shiv 21000 Computer Sc Nagpur
Name Place Samira Ahmedabad Suman Ahmedabad Shalaka Jaipur
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