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Question
Write the reaction when ethylamine is treated with excess of ethyl bromide.
Chemical Equations/Structures
Very Short Answer
Solution
When ethylamine (C2H5NH2) is treated with excess ethyl bromide (C2H5Br), it undergoes alkylation, forming tetraethylammonium bromide (C2H5)4N+Br−.
\[\ce{C_2H_5NH_2 + 3C_2H_5Br -> (C_2H_5)_4N^+Br^-}\]
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