Advertisements
Advertisements
Question
`x^2-(2b-1)x+(b^2-b-20)=0`
Solution
We write, -(2b-1)x=-(b-5)x-(b+4)x as
x^2xx(b^2-b-20)=(b^2-b-20)x^2=[-(b-5)x]xx[-(b+4)x]
∴ `x^2-(2b-1)x+(b^2-b-20)=0`
⇒ `x^2-(b-5)x-(b+4)x+(b+4)=0`
⇒`x[x-(b-5)]-(b+4)[x-(b-5)]=0`
⇒` [x-b-5]x- [b+4]=0`
⇒`x-(b-5)=0 or x-(b+4)=0`
⇒ `x=b-5 or x=b+4`
Hence, b - 5 and b + 4 are the roots of the given equation.
APPEARS IN
RELATED QUESTIONS
Check whether the following is quadratic equation or not.
16x2 − 3 = (2x + 5) (5x − 3)
Solve the following equation and give your answer correct to 3 significant figures: 5x² – 3x – 4 = 0
Solve:
(x2 + 5x + 4)(x2 + 5x + 6) = 120
Without solving, comment upon the nature of roots of the following equation:
25x2 − 10x + 1 = 0
Solve : x4 - 10x2 +9 =0
Check whether the following are quadratic equations: `x + (2)/x = x^2, x ≠ 0`
Choose the correct answer from the given four options :
Which of the following is not a quadratic equation?
Choose the correct alternative answer for the following sub questions and write the correct alphabet.
Which of the following is not a quadratic equation?
If the sum of the roots of a quadratic equation is 5 and the product of the roots is also 5, then the equation is:
Which of the following is not a quadratic equation?
