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Question
x is 5% of y, y is 24% of z. If x = 480, find the values of y and z.
Solution
Given:
\[x = \frac{5}{100}y \]
\[ \Rightarrow y = \frac{100}{5}x\]
\[ \therefore y = 20x\]
\[\text{ Also, } y = \frac{24}{100}z\]
\[ \therefore z = \frac{100}{24}y\]
\[\text{ Putting }x = 480\text{ in the above equations, we get: }\]
\[y = 20\left( 480 \right) = 9600\]
\[z = \frac{100}{24} \times 9600 = 40000\]
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