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Question
\[\ce{X <-[red P][HI] CH3COOH ->[LiAlH4] Y.}\]
What does Not true for X and Y?
Options
X is hydrocarbon of general formula CnH2n+2 while Y belong to alkanol
X can be obtained by reducing CH3CH2Cl while Y by its hydrolysis
X gives positive litmus test but Y does not
X and Y both belong to different homologeous series
MCQ
Solution
X is hydrocarbon of general formula CnH2n+2 while Y belong to alkanol
Explanation:
\[\ce{\underset{[X] = hydrocarbon}{CH3-CH3} <-[red P][HI] CH3COOH ->[LiAlH4]\underset{[Y] alkanol}{CH3CH2OH}}\]
Y give positive litmus test but 'X' does not.
shaalaa.com
Alkanes - Preparation of Alkanes from Unsaturated Hydrocarbons, Alkyl Halides and Carboxylic Acids
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